SOLUTION: 1. Two cards are selected without replacement from a usual deck of 52 cards. [A deck of cards has four suits (hearts, diamonds, spades, clubs) and each suit has 13 cards (2 to 10,

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Question 665553: 1. Two cards are selected without replacement from a usual deck of 52 cards. [A deck of cards has four suits (hearts, diamonds, spades, clubs) and each suit has 13 cards (2 to 10, J, Q, K, A).]
(a) Find
the following probabilities:
(i) both cards are red cards;
(ii) both cards are kings
(iii) oneofthecardsisthekingofhearts
(iv) at least one of the cards is a red card or a face card (J, Q, K)
(v) exactly one of the cards is a king.

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Two cards are selected without replacement from a usual deck of 52 cards. [A deck of cards has four suits (hearts, diamonds, spades, clubs) and each suit has 13 cards (2 to 10, J, Q, K, A).]
(a) Find
the following probabilities:
(i) both cards are red cards;
Ans: 26C2/52C2 =
---------------------------
(ii) both cards are kings
Ans 4C2/52C2
-----------------------------
(iii) exactly oneofthecardsisthekingofhearts
Ans (2*4C1*48C1)/52C2 = 8/52C2
-----------------------------------
(iv) at least one of the cards is a red card or a face card (J, Q, K)
Ans: [26C2+ 12C2 - 6C2]/52C2
-------------------------------------
(v) exactly one of the cards is a king.
Ans: (2*4C1*48C1)/52C2
=============================
Cheers,
Stan H.
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