SOLUTION: There are 9 letters; 5 consonants and 4 vowels. Three letters are chosen at random. What is the probability of choosing more than one vowel?

Algebra.Com
Question 664282: There are 9 letters; 5 consonants and 4 vowels. Three letters are chosen at random. What is the probability of choosing more than one vowel?
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
There are 9 letters; 5 consonants and 4 vowels. Three letters are chosen at random. What is the probability of choosing more than one vowel?
----
P(choose more than one vowel) = 1 - P(choose no vowels)
----
= 1 - 5C3/9C3
----
= 1 - 0.1190
-----
= 0.8810
=================
Cheers,
Stan H.

RELATED QUESTIONS

Please help me. A word consist of 5 consonants and 4 vowels. Three letters are selected... (answered by edjones)
I have a bag full of letters. there are 4 vowels and 9 consonants. I pull out letters... (answered by ewatrrr)
The word geometry has eight letters. Three letters are chosen at random. What is the... (answered by Fombitz)
a) In how many different ways can the letters of the word KNOWLEDGE be arranged in such a (answered by ikleyn)
The letters of DIRECTOR are arranged at random. What is the probability of vowels... (answered by Edwin McCravy)
Dear math teacher, I am having diffulties with the following problem: Find the... (answered by stanbon)
The alphabet contains 26 letters, 5 of them are vowel. How many codes consisting of 5... (answered by Edwin McCravy)
In the small country of Mathland, all automobile license plates have four symbols. The... (answered by greenestamps)
a set contains the first ten letters of english alphabet.how many different alphabets of... (answered by MIT0053)