SOLUTION: The television show Found has been successful for many years. That show recently had a share of 27, meaning that among the TV sets in use, 27% were tuned to Found. Assume that an
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Question 663918: The television show Found has been successful for many years. That show recently had a share of 27, meaning that among the TV sets in use, 27% were tuned to Found. Assume that an advertiser wants to verify that 27% share value by conducting its own survey, and a pilot survey begins with 15 households have TV sets in use at the time of a Found broadcast.
Find the probability that none of the households are tuned to Found.
P(none) =
Find the probability that at least one household is tuned to Found.
P(at least one) =
Find the probability that at most one household is tuned to Found.
P(at most one) =
I am not sure how to even start this problem to be completely honest.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Just curious: You said, and I quote: "...to be completely honest." To me, that means that previous to having made that statement, you were less than completely honest. So what is it about the earlier part of your post that is dishonest? Please continue to be completly honest or at least warn me when you begin to dissemble or otherwise communicate falsehoods.
The probability of 
successes in 
trials where 
is the probability of success on any given trial is given by:
\ =\ {{n}\choose{k}}\left(p\right)^k\left(1\,-\,p\right)^{n\,-\,k})
Where 
is the number of combinations of things taken at a time and is calculated by !})
The probability of none is then:
\ =\ {{15}\choose{0}}\left(0.27\right)^0\left(1\,-\,0.27\right)^{15\,-\,0})
and the probability of one is:
\ =\ {{15}\choose{1}}\left(0.27\right)^1\left(1\,-\,0.27\right)^{15\,-\,1})
\ =\ 1\ =\ P(0))
\ =\ P(1)\ +\ P(0))
John
My calculator said it, I believe it, that settles it
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