If a boy tosses a coin twice, and if the last result is a tail, he throws a die
(a) How many possible final outcomes are there?
Outcome 1: H, H Probability = (1/2)(1/2) = 1/4
Outcome 2: H, T, 1 Probability = (1/2)(1/2)(1/6) = 1/24
Outcome 3: H, T, 2 Probability = (1/2)(1/2)(1/6) = 1/24
Outcome 4: H, T, 3 Probability = (1/2)(1/2)(1/6) = 1/24
Outcome 5: H, T, 4 Probability = (1/2)(1/2)(1/6) = 1/24
Outcome 6: H, T, 5 Probability = (1/2)(1/2)(1/6) = 1/24
Outcome 7: H, T, 6 Probability = (1/2)(1/2)(1/6) = 1/24
Outcome 8: T, H Probability = (1/2)(1/2) = 1/4
Outcome 9: T, T, 1 Probability = (1/2)(1/2)(1/6) = 1/24
Outcome 10: T, T, 2 Probability = (1/2)(1/2)(1/6) = 1/24
Outcome 11: T, T, 3 Probability = (1/2)(1/2)(1/6) = 1/24
Outcome 12: T, T, 4 Probability = (1/2)(1/2)(1/6) = 1/24
Outcome 13: T, T, 5 Probability = (1/2)(1/2)(1/6) = 1/24
Outcome 14: H, T, 6 Probability = (1/2)(1/2)(1/6) = 1/24
So there are 14 outcomes, but they are not all equally likely.
(b)what is the probability of getting a head, tail and a 6 in that order
That's the outcome I colored red above. That's
Edwin