Hi,

134 golfers: m = 87.43  and s = 4.53

(A) Find the 99% confidence interval of the mean score for all 134 golfers.

  ME = 

the 99% confidence interval:

  87.43 - ME <  < 87.43 + ME

99% confidence interval of the mean score for all golfers if this is a sample of 105 golfers

  ME = 

  87.43 - ME <  < 87.43 + ME

(C) Which confidence interval is smaller and why

  larger sample has a smaller confidence interval as the ME is smaller

 

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