SOLUTION: This question was answered, but the answer confused me even more - So I will enter the Table we are to use also then maybe you folks can help unconfuse me. Problem: If we wish to

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Question 662459: This question was answered, but the answer confused me even more - So I will enter the Table we are to use also then maybe you folks can help unconfuse me.
Problem: If we wish to have a 99% confidence interval, what would be the value of the confidence coefficient, z(a/2)? (Use Table 4B)
Table 4B:
a.....0.25...0.20...0.10...0.05...0.02...0.01
z(a/2..1.15...1.28..1.65...1.96...2.33...2.58
1-a....0.75...0.80..0.90...0.95...0.98...0.99
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 

Hi,

certainly can understand Your diligence...

translating .995 to a z-value gives 2.58

Table 4B: 

  a.....0.25...0.20...0.10...0.05...0.02...0.01  Percents listed as decimals

z(a/2)..1.15...1.28..1.65...1.96...2.33...

 1-a....0.75...0.80..0.90...0.95...0.98...0.99   Percents listed as decimals

 1-a/2....0.875...0.90..0.95...0.975...0.99...0.995 and NORMSDIST(.995) = 2.58   

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