SOLUTION: A poll taken by a TV news organization reported a margin of error of 3.5
percentage points. Approximately what sample size was the poll?
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Question 657440: A poll taken by a TV news organization reported a margin of error of 3.5
percentage points. Approximately what sample size was the poll?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A poll taken by a TV news organization reported a margin of error of 3.5
percentage points. Approximately what sample size was the poll?
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ME = z*(s/sqrt(n))
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3.5 = z*s/sqrt(n)
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To estimate "n" you need to know z and s.
Cheerx,
Stan H.
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