SOLUTION: Hi, I really need help with this problem its been years since I took math 5 and this is driving me crazy.. can anyone explain step by step to me please? i will really appreciate it

Question 656328: Hi, I really need help with this problem its been years since I took math 5 and this is driving me crazy.. can anyone explain step by step to me please? i will really appreciate it..
If i draw two cards at once (without replacement, find the following probabilities?
a) at least one face card
b) exactly one face card or one ace (but not one of each)
c) one spade and one heart
d) at least one face card or one club
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

At least one face. Difficult to calculate straight up, so go at the problem from a different direction. If you have drawn 2 cards, then there are exactly four possible situations that could occur, namely: 2 face, 1st one is a face and the second not, the 1st one is not a face and the second one is, and then no face cards at all. The sum of these four probabilities must be 1 because they are the only four things that can happen.

So, the easy way to calculate the probability of any of the first three situations occuring is to calculate the probability of the fourth situation and subtracting that value from 1.

The probability that the first card drawn is NOT a face card is the number of non-face cards in a deck divided by the number of cards in the deck, or

which reduces to

. Now, assuming that the first card drawn was a non-face, there are now a total of 39 non-face cards left in a deck that consists of 51 cards, hence the probability on the second draw is

. Since the two events as described are independent of each other, the probability of both is the product of their individual probabilities.

John

My calculator said it, I believe it, that settles it

The Out Campaign: Scarlet Letter of Atheism

RELATED QUESTIONS
Hi I really need help with this math problem-----> find the... (answered by Theo)

Hi my name is Baylee and I really need help in math and I was wondering if you can help... (answered by Alan3354)

hy i have this math problem and its really stressing me out can anyone help?..i have to... (answered by rothauserc)

Expand and simplify: ln(xe) Thats the problem that has been driving me crazy. I dont... (answered by venugopalramana)

Hi tutor, i really need help with this question. Im a really hard worker, and ive been... (answered by nerdybill)

Hi! I'd like to ask help on this problem since I'm not sure if all I had to do was to... (answered by Theo)

X+3 X _________ - _____ = X 4 2 I have worked this problem for... (answered by Mathtut)

Use slopes to show that the square with virtices at (-2,5), (4, 5), (4, -1), and (-2, -1) (answered by stanbon)

I need help with this one math problem. Is there any way you can help... (answered by rfer)