Hi,

Don't know what You have been using to determine  standard deviationetc in general:

If you have a TI 83 calculator,might recommend this tutorial site:

http://www.tc3.edu/instruct/sbrown/ti83/regress.htm

 where 

s[x]= sqrt and s[y] = sqrt

and  

In the normal Work Up using an Excel Worksheet, there is a need to sum (xi - 2.5)(yi - 78.2) as well 

       (xi-2.5)^2 (yi-78.2)^2 (xi-2.5)(yi-78.2)

	6.25	475.24	-54.5

	2.25	190.44	-20.7

	0.25	14.44	-1.9

	0.25	0.04	-0.1

	2.25	148.84	-18.3

	6.25	739.84	-68

Sum	17.5	1568.84	-163.5

       

		33.14	

 = -32.7/33.14 = -.9867

Regression Line 1s:  y = ax + b,  where

a =  

 and 

a = -163.5/17.5 = -9.34

 = 100.5

y = -9.34x + 100.5

 

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