# SOLUTION: A box contains 21 transistors, 7 of which are defective. If 7 are selected at random, find the probabpility that: A. All are defective B. None are defective

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 Click here to see ALL problems on Probability-and-statistics Question 649298: A box contains 21 transistors, 7 of which are defective. If 7 are selected at random, find the probabpility that: A. All are defective B. None are defectiveAnswer by stanbon(57250)   (Show Source): You can put this solution on YOUR website!A box contains 21 transistors, 7 of which are defective. If 7 are selected at random, find the probabpility that: Binomial Problem with n = 21 ; P(defective) = 7/21 = 1/3 ; P(good) = 2/3 A. P(All are defective) = (1/3)^7 = 0.0004572... ------ B. P(None are defective) = (2/3)^7 = 0.0585 =================== Cheers, Stan H. ================