SOLUTION: The weights of adult Asian palm civets are known to be normally distributed with a mean of 7.7 pounds and a standard deviation of 0.95 pounds. What is the probability that a r

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Question 646101: The weights of adult Asian palm civets are known to be normally distributed with
a mean of 7.7 pounds and a standard deviation of 0.95 pounds. What is the
probability that a randomly selected civet will:
A. Weigh at least 6 pounds?
B. Weigh less than 5 pounds or more than 10 pounds?
Please help, i'm so confused! thank you

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
mean of 7.7 pounds and a standard deviation of 0.95 pounds
Using TI-83 Calculator to Compute Normal Probability Distribution Values:
Press 2nd VARS [DISTR].Scroll down to 2:normalcdf and Press ENTER:
Enter proper values, Press ENTER.
P(Weigh at least 6 pounds) is normalcdf(6,9999,7.7,.95)
Note: The 9999 is used as the larger value to be at least 5 standard deviations from the mean.
P(Weigh less than 5 pounds or more than 10 pounds) = 1 - P(5 ≤ x ≤ 10)
= 1 - normalcdf(5,10,7.7,.95)
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