Hi,
Assume that the population of heights of female college students is
approximately normally distributed with mean m of 66.24 inches and standard
deviation s of 5.07 inches. A random sample of 72 heights is obtained
(A) Find P(x>65.75) = P()Find z and then determine corresponding P-value
(B) Find the mean and standard error of the xbar distribution
mean = 66.24, SD =
(C) Find P(x >65.75)= P()Find t and then determine corresponding P-value
(D) Why is the formula required to solve (A) different than than (C)?
x is a sample mean