SOLUTION: Assume that a trait is determined by a single pair of genes where one allele is dominant and the other is recessive. Suppose a hybrid mates with a pure dominant. If they produce

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Assume that a trait is determined by a single pair of genes where one allele is dominant and the other is recessive. Suppose a hybrid mates with a pure dominant. If they produce two offspring, what is the probability that neither is a hybrid?
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It sounds like the hybrid has a dominant and a recessive and the
pure dominant has two dominants.
So we want the probability that neither of two offspring are hybrid.
Both would have to have two recessive or two dominant.
P(2 recessive in one birth) = (1/4)(1/4)=1/16
P(2 recessive in two births)=1/16*1/16=1/256
P(2 dominant in one birth)= 3/4*3/4=9/16
P(2 dominant in two births)=9/16*9/16=81/256
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Prob(neither are hybrids in two births)=1/256*81/256=81/65536
Cheers,
Stan H.