SOLUTION: On a table, there are 50 good pens and 10 defective pens. In how many ways can 25 pens be selected so that exactly 3 are defective?

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Question 639088: On a table, there are 50 good pens and 10 defective pens. In how many ways can 25 pens be selected so that exactly 3 are defective?
Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
On a table, there are 50 good pens and 10 defective pens. In how many ways can 25 pens be selected so that exactly 3 are defective?
"50 choose 22" TIMES "10 choose 3" = C(50,22)×C(10,3) = 1.065 × 1016

Edwin
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