SOLUTION: Twenty-six small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 44.5 ca

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Question 635420: Twenty-six small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 44.5 cases per year.
(a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)
lower limit =
upper limit =
margin of error =
(b) Find a 95% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)

lower limit =
upper limit =
margin of error =
(c) Find a 99% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)
lower limit =
upper limit =
margin of error =

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 

Hi,

Note:  z-values for various confidence levels

90%	z = 1.645

95%	z = 1.96

98%	z = 2.33

99%	z = 2.576

a) ME =  1.645(44.5/sqrt(10000)= .732

 138.5 - ME <  < 138.5 + ME

b)ME =  1.96(44.5/sqrt(10000)= .873

 138.5 - ME <  < 138.5 + ME

c)ME =  2.576(44.5/sqrt(10000)= 1.146

 138.5 - ME <  < 138.5 + ME 

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