SOLUTION: Find the standard deviation o for the binomial distribution which has the stated value of n and p round to nearest hundredth n=45 p= 0.2

Question 633873: Find the standard deviation o for the binomial distribution which has the stated value of n and p round to nearest hundredth n=45 p= 0.2
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Standard Deviation

sigma = sqrt(np(1-p))

sigma = sqrt(45*0.2(1-0.2))

sigma = 2.68328

sigma = 2.68

So the standard deviation is roughly 2.68

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Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the standard deviation o for the binomial distribution which has the stated value of n and p round to nearest hundredth n=45 p= 0.2
----
q = 0.8
----
sigma = sqrt(npq) = sqrt(45*0.2*0.8) = 2.6833
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Cheers,
Stan H.
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