SOLUTION: Given the mean equal to 26 and the standard deviation equal to 3, what is the chance that a value of X greater than 18 will occur?

Question 633328: Given the mean equal to 26 and the standard deviation equal to 3, what is the chance that a value of X greater than 18 will occur?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Given the mean equal to 26 and the standard deviation equal to 3, what is the chance that a value of X greater than 18 will occur?
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z(18) = (18-26)/3 = -8/3
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P(x > 18) = P(z > -8/3) = normalcdf(-8/3,100) = 0.9962
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Cheers,
Stan H.
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