Hi,

Calculate the Expected Value(Sum of PX) = μ = 0

Then Calculate the Variance(Sum of P[X-μ]^2) = 2.94

SD =  

X	P	PX	P[X-μ]^2    

-4	0.02	-0.08	0.32   

-3	0.07	-0.21	0.63

-2	0.1	-0.2	0.4

-1	0.15	-0.15	0.15

0	0.3	0	0

1	0.18	0.18	0.18

2	0.1	0.2	0.4

3	0.06	0.18	0.54

4	0.02	0.08	0.32

Sum		0	2.94

 

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