SOLUTION: The lottery in Combinatoricsville has two parts. A winner has satistied part A and part B. Part A: Pick the 5 winning numbers from 1, …, 30. Part B: Pick the two winning numbers,

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: The lottery in Combinatoricsville has two parts. A winner has satistied part A and part B. Part A: Pick the 5 winning numbers from 1, …, 30. Part B: Pick the two winning numbers,      Log On

Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 632024: The lottery in Combinatoricsville has two parts. A winner has satistied part A and part B.
Part A: Pick the 5 winning numbers from 1, …, 30.
Part B: Pick the two winning numbers, in the correct order, from 1, … , 5.
What is the probability of winning this lottery?
Answer by Edwin McCravy(8999) About Me  (Show Source):
You can put this solution on YOUR website!
The lottery in Combinatoricsville has two parts. A winner has satistied part A and part B.
Part A: Pick the 5 winning numbers from 1, …, 30.
The probability of getting that right is 1%2FC%2830%2C5%29

Part B: Pick the two winning numbers, in the correct order, from 1, … , 5.
What is the probability of winning this lottery?
1. If that means that choosing 2 then 4 is not the same as choosing 4 then 2

the probability of getting that right is 1%2FP%285%2C2%29

And the final answer is 1%2FC%2830%2C5%29×1%2FP%285%2C2%29 which is
approximately .000000351

2. If that means that choosing 2 then 4 is the same as choosing 4 then 2

the probability of getting that right is 1%2FC%285%2C2%29

And the final answer is 1%2FC%2830%2C5%29×1%2FC%285%2C2%29 which is
approximately .0000000702 

Edwin