SOLUTION: for a normal distribution that has a mean of 100 and a standard deviation of 8, what is the z score for x=98, x=108 and x= 112

Question 629340: for a normal distribution that has a mean of 100 and a standard deviation of 8, what is the z score for x=98, x=108 and x= 112
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
z = (x - mu)/(sigma)

z = (x - 100)/(8)

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z score for x = 98

z = (x - 100)/(8)

z = (98 - 100)/(8)

z = (-2)/(8)

z = -0.25
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z score for x = 108

z = (x - 98)/(8)

z = (108 - 100)/(8)

z = (8)/(8)

z = 1

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z score for x = 112

I'll let you do this one

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