# SOLUTION: Scores on the Stanford-Binet Intelligence scale have a mean of 100 and a standard deviation of 16, and are presumed to be normally distributed. A person who scores a 132 on this s

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: Scores on the Stanford-Binet Intelligence scale have a mean of 100 and a standard deviation of 16, and are presumed to be normally distributed. A person who scores a 132 on this s      Log On

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 Algebra: Probability and statistics Solvers Lessons Answers archive Quiz In Depth

 Question 629189: Scores on the Stanford-Binet Intelligence scale have a mean of 100 and a standard deviation of 16, and are presumed to be normally distributed. A person who scores a 132 on this scale has what percentile rank within the population? Show all work as to how this is obtained.Answer by stanbon(57290)   (Show Source): You can put this solution on YOUR website!Scores on the Stanford-Binet Intelligence scale have a mean of 100 and a standard deviation of 16, and are presumed to be normally distributed. A person who scores a 132 on this scale has what percentile rank within the population? Show all work as to how this is obtained. ----- z(132) = (132-100)/16 = 2 %ile rank: P(x < 2) = 97.72 Rounded up the %ile rank = 98%ile ==================================== Cheers, Stan H.