SOLUTION: A man has 7 nickels and 5 quarters in his pocket. He removes two coins without replacement. Find the probability that both are quarters.

Question 628673: A man has 7 nickels and 5 quarters in his pocket. He removes two coins without replacement. Find the probability that both are quarters.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A man has 7 nickels and 5 quarters in his pocket. He removes two coins without replacement. Find the probability that both are quarters.
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# of ways to succeed: 5C2 = 10
# of possible outcomes: 12C2 = 66
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P(2 quarters) = 10/66 = 5/33
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Cheers,
Stan H.
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