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put this solution on YOUR website!A family has five children. The probablilty of having a girl is 1/2. What is the probability of having no more than 3 boys?
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P(0<=X<=3)= binomcdf(5,.5,3)=0.81
This from using a TI-83
another way is 1-[P(X=4)+P(X=5)]
P(x=4)=5C4(1/2)^5
P(x=5)=1/32
Cheers,
Stan H.
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