Hi,

MEAN = 230 with a standard deviation of 22

 .10  ⇒ Z = -1.2816 = (X-230)/22  OR X = 

 .90  ⇒ Z = 1.2816 = (X-230)/22  OR X = 

What number of fish per trap would he expect in the interval symmetrical about the mean 

where 80% of the numbers would be found.  202 to 258 fish per trap  





 

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