SOLUTION: Roll total (die 1, die 2) Number of combinations Probability 2 (1,1) 1 1/36 3 (1,2) or (2,1) 2 2/36 4 (1,3), (2,2), (3,1) 3 3/36 5 (1,4), (2,3

Question 625745: Roll total (die 1, die 2) Number of combinations Probability

2 (1,1) 1 1/36
3 (1,2) or (2,1) 2 2/36
4 (1,3), (2,2), (3,1) 3 3/36
5 (1,4), (2,3), (3,2),(4-1) 4 4/36
6 (1,5), (2,4), (3,3), (4,2), (5,1) 5 5/36
7 (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) 6 6/36
8 (2,6), (3,5), (4,4), (5,3), (6-2) 5 5/36
9 (3,6), (4,5), (5,4), (6,3) 4 4/36
10 (4,6), (5,5), (6,4) 3 3/36
11 (5,6) or (6,5) 2 2/36
12 (6,6) 1 1/36

Total _36__
Using the above probabilities, the probability of rolling a 5 or a 7 is: _____?

Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
Answer: 5/18
If you have any doubt or if you have more problems my e-mail is:
mthman@gmail.com

RELATED QUESTIONS
1/2(36)+6=1/3(36) (answered by krilly233)

1/2(36)+6=1/3(36) (answered by krilly233)

When solving this problem and using PEMDAS, have I done this correctly?:... (answered by rapaljer)

A fair die is rolled. What is the probability of rolling a 3 or a 4? Possible Answers: (answered by fractalier)

A six sided die was rolled 12 times with these results: roll- 1, 2, 3, 4, 5, 6 times-... (answered by greenestamps)

X 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12 P(X) 1/36 2/36 3/36 4/36 5/36 (answered by Solver92311)

X 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12 P(X) 1/36 2/36 3/36 4/36 5/36 (answered by robertb)

1. Calculate the probability of the following the sequential roll of the die faces (answered by mathhelper123)

{{{ matrix(2,1,"", 2(x-1)^(3/4)+4=36) }}} (answered by jsmallt9,Edwin McCravy)