SOLUTION: If I have 16 smokers out of a possible 63 and I choose 3 people at random from the 63 what is the probability that exactly 2 of them will be smokers?
Hi
16 smokers out of a possible 63: .254 smoke & .746 do not smoke
choosing 3 people at random from the 63 ...
P(2 smoke 'and' one does not) = (.254)^2(.746)