SOLUTION: If Steve can mix 20 drinks in 5 minuets, Sue can mix 20 drinks in 10 minuets, and Jack can mix 20 drinks in 15 minuets, how much time will it take all 3 of them working together to
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-> SOLUTION: If Steve can mix 20 drinks in 5 minuets, Sue can mix 20 drinks in 10 minuets, and Jack can mix 20 drinks in 15 minuets, how much time will it take all 3 of them working together to
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Question 614712: If Steve can mix 20 drinks in 5 minuets, Sue can mix 20 drinks in 10 minuets, and Jack can mix 20 drinks in 15 minuets, how much time will it take all 3 of them working together to mix 20 drinks?? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! If Steve can mix 20 drinks in 5 minuets, Sue can mix 20 drinks in 10 minuets, and Jack can mix 20 drinks in 15 minuets, how much time will it take all 3 of them working together to mix 20 drinks??
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Since they are all doing the same job, mixing of 20 drinks, we can call the completed job 1
:
Each will do a fraction of the job, the three fractions will add up to 1
: + + = 1
multiply by 30 to clear the denominators
30* + 30* + 30* = 30
cancel the denominators
6t + 3t + 2t = 30
11t = 30
t = , about 2.73 minutes or 2 min 43.6 sec
