SOLUTION: 16 Blue , 9 Red ,13 Green ,9 Yellow , 11 Orange, 8 Brown Choose one M&M at random a) P(Blue) b) P(Red or Brown)? Choose Two M&M'S without replacement a) P

Algebra ->  Probability-and-statistics -> SOLUTION: 16 Blue , 9 Red ,13 Green ,9 Yellow , 11 Orange, 8 Brown Choose one M&M at random a) P(Blue) b) P(Red or Brown)? Choose Two M&M'S without replacement a) P      Log On


   

Question 614208: 16 Blue , 9 Red ,13 Green ,9 Yellow , 11 Orange, 8 Brown
Choose one M&M at random
a) P(Blue) b) P(Red or Brown)?

Choose Two M&M'S without replacement
a) P(Blue then Green)? b)P( Yellow then Yellow)?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, 

16 Blue , 9 Red ,13 Green ,9 Yellow , 11 Orange, 8 Brown. 66 M&Ms in all.

Choose one M&M at random 

a) P(Blue) = 16/66 = 8/33            

b) P(Red 'or' Brown) = 9/66 + 8/66 = 17/66

Choose Two M&M'S without replacement 

a) P(Blue then Green) = %2816%2F66%29%2813%2F65%29+

b)P( Yellow then Yellow)= %289%2F66%29%288%2F65%29