Hi, 

16 Blue , 9 Red ,13 Green ,9 Yellow , 11 Orange, 8 Brown.  M&Ms in all.

Choose one M&M at random 

a) P(Blue) = 16/66 = 8/33            

b) P(Red 'or' Brown) = 9/66 + 8/66 = 17/66

Choose Two M&M'S without replacement 

a) P(Blue then Green) = 

b)P( Yellow then Yellow)=  

RELATED QUESTIONS

1.69oz. bag of plain M&M's
Total in bag: 57
Red: 6 -11%
Yellow: 7 - 12%
Orange: 8 -... (answered by checkley77)

According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s... (answered by math_tutor2020)

In a bag of M&M’s there are 12 green, 7 blue, 11 brown, 9 orange,  and 15 red candies.... (answered by MathGeek87,swincher4391)

Please help me solve this question.


The Web site for M&Mâ„¢ candies claimed that 24%  (answered by Boreal)

The Web site for M&Mâ„¢ candies claimed that 24% of plain M&M candies are blue, 20% are... (answered by CPhill)

The color of M&M candies can be brown,yellow, red, blue, orange and green. The following... (answered by Fombitz)

You are hungry for M& M's. If the bag is made up of 20%,20%red,and orange,blue,and green... (answered by ewatrrr)

According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are... (answered by ikleyn)

(There is 3 Blue, 8 Red, 12 Green, 12 Yellow, 4 Brown, and 2 Orange.)

When you open a... (answered by ewatrrr)