SOLUTION: Joy has seven pairs of shoes. three are ivory and four are navy. She randomly chooses a pair to wear each day. Find the probability that Joy chooses a ivory pair two days in a r

Question 614121: Joy has seven pairs of shoes. three are ivory and four are navy. She randomly chooses a pair to wear each day. Find the probability that Joy chooses a ivory pair two days in a row under each condition.
Will she wear the same pair two days in a row or will she not wear the same pair two days in a row
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Joy has seven pairs of shoes. three are ivory and four are navy. She randomly chooses a pair to wear each day. Find the probability that Joy chooses a ivory pair two days in a row under each condition.
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P(pick an ivory pair) = 3/7
P(pick ivory pair 2 days in a row) = (3/7)^2 = 9/49
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Will she wear the same pair two days in a row or will she not wear the same pair two days in a row.
That is up to Joy.
Cheers,
Stan H.

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