SOLUTION: Please help me with this one. In previous test, baseballs were dropped 24ft. onto a concrete surface, and they bounced an average of 92.84 in. In a test of a sample of 40 new balls

Question 61325This question is from textbook Elementary Statistics
: Please help me with this one. In previous test, baseballs were dropped 24ft. onto a concrete surface, and they bounced an average of 92.84 in. In a test of a sample of 40 new balls, the bounce heights had a mean of 92.67 in. and a standard deviation of 1.79 in(based on data from Brookhaven National Laboratory). Use a 0.05 significance level to determine whether there is sufficient evidence to support the claim that the new balls have bounce heights with a mean different from 92.84 in. Does it appear that the new baseball are different?
My solution:
t = 92.67-92.84/1.79/sq.root of 40 = -0.17/.2830238 = -.6006
I think claim is p not equal to .9284, so null hyphotesis is p = .9284
alternative hyphotesis p not equal to .9284
This is a two-tailed test and Critical value is +- 1.96
Where do I base my answer ? Do I need P value for this problem?
Thank you for all your help.
Jo This question is from textbook Elementary Statistics

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In previous test, baseballs were dropped 24ft. onto a concrete surface, and they bounced an average of 92.84 in. In a test of a sample of 40 new balls, the bounce heights had a mean of 92.67 in. and a standard deviation of 1.79 in(based on data from Brookhaven National Laboratory). Use a 0.05 significance level to determine whether there is sufficient evidence to support the claim that the new balls have bounce heights with a mean different from 92.84 in. Does it appear that the new baseball are different?
My solution:
t = 92.67-92.84/1.79/sq.root of 40 = -0.17/.2830238 = -0.6006
I think claim is p not equal to 92.84, so null hyphotesis is p = 92.84
alternative hyphotesis p not equal to 92.84
This is a two-tailed test and Critical value is +- 1.96
Comment:
Where do I base my answer ?
Your t-value of -0.6006 is not in the critical region below
z=-1.96 so you "Fail to reject Ho" which was mu=92.84
Do I need P value for this problem?
Not really. But the p-value is 0.55 which is greater
than alpha= 0.05 and supports the conclusion of "Fail to reject Ho".
Cheers,
Stan H.
Thank you for all your help.
Jo
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