Hi, Re:TY, 

The display below are the  possible outcomes rolling a pair of dice

Only one of the outcomes is >9 'and' is a 12, thus the 1/36

There are 6 possible outcomes >9 and therefore the 6/36

P(A|B) = P(A and B)/P(B)

P(12|>9) =  = 1/6



___1_2_3__4__5__6

1|_2_3_4__5__6__7

2|_3_4_5__6__7__8

3|_4_5_6__7__8__9

4|_5_6_7__8__9_10

5|_6_7_8__9_10_11

6|_7_8_9_10_11_

 

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