SOLUTION: Please help me to answer this. I am as lost as I can be. I truly need you.
If an island’s only residents are penguins and
bears, and if there are 15 heads and 36 feet on the
i
Algebra.Com
Question 612572: Please help me to answer this. I am as lost as I can be. I truly need you.
If an island’s only residents are penguins and
bears, and if there are 15 heads and 36 feet on the
island, how many penguins and how many bears
are on the island?
Found 2 solutions by scott8148, stanbon:
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
bears have 4 feet and penguins have 2 ___ they both have one head
b + p = 15
4b + 2p = 36 ___ 2b + p = 18
subtracting the 1st equation from the 2nd equation ___ b = 3
substitute back to find p
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If an island’s only residents are penguins and
bears, and if there are 15 heads and 36 feet on the
island, how many penguins and how many bears
are on the island?
-------------------------
Heads: p + b = 36
Feet: 2p +4b = 36
-------------------
Multiply thru the Heads equation by 2:
2p + 2b = 72
2p + 4b = 36
-----
Subtract and solve for "b":
2b = 36
b = 18 (# of bears)
-----
solve for "P":
p + b = 36
p + 18 = 36
p = 18 (# of penquins)
==========================
Cheers,
Stan H.
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