SOLUTION: was reported in a medical journal that about 70% of the individuals needing a kidney transplant find a suitable donor when they turn to registries of unrelated donors. In a group o
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Question 61164: was reported in a medical journal that about 70% of the individuals needing a kidney transplant find a suitable donor when they turn to registries of unrelated donors. In a group of fifteen individuals needing a kidney transplant, find the probability that:
a) Less than ten will find a suitable donor among the registries of unrelated donors.
b) Exactly eight will find a suitable donor among the registries of unrelated donors.
c) At least fourteen will find a suitable donor among the registries of unrelated donors.
d) No more than five will find a suitable donor among the registries of unrelated donors.
e) Six or less will find a suitable donor among the registries of unrelated donors.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
was reported in a medical journal that about 70% of the individuals needing a kidney transplant find a suitable donor when they turn to registries of unrelated donors. In a group of fifteen individuals needing a kidney transplant, find the probability that:
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Comment: These are all binomial probability problems with p=0.7 and n=15.
I used a TI-83 to find the probabilities. You might have to use some other
calculator or your binomial tables.
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a) Less than ten will find a suitable donor among the registries of unrelated donors.
P(0
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b) Exactly eight will find a suitable donor among the registries of unrelated donors.
P(X=8)=binompdf(15,0.7,8)=0.08
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c) At least fourteen will find a suitable donor among the registries of unrelated donors.
P(X>=14)= 1-P(X<=13) = 1- binomcdf(15,0.7,13)= 1-0.964732...=0.035...
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d) No more than five will find a suitable donor among the registries of unrelated donors.
P(X<=5)=binomcdf(15,0.7,5)=0.00365...
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e) Six or less will find a suitable donor among the registries of unrelated donors.
P(X<=6)=binomcdf(15,0.7,6)=0.01524...
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Cheers,
Stan H.
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