SOLUTION: the body temperature of healthy children is normally distributed with mean 98.6 F and standard deviation 0.9 F. If one healthy child is selected at random, what is the probabili

Question 610781: the body temperature of healthy children is normally distributed with mean 98.6 F and standard deviation 0.9 F.
If one healthy child is selected at random, what is the probability that the body temperature is more than 99.6 F?
If six healthy children are chosen at random, what is the probability that the mean body temperature x for all six is more than 99.6F?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi, 

body temperature of healthy children is normally distributed with mean 98.6 F and standard deviation 0.9 F.

 If one healthy child is selected at random:

P(temp>99.6)= P(z> (99.9-98.6)/.9) = P(z> 1.7778) = .0377

If six healthy children are chosen at random: 

P(6 with temp >99.6) = (.0377)^6 

RELATED QUESTIONS

Healthy people have body temperatures that are normally distributed with a mean of 98.20... (answered by MathLover1)
The body temperatures of adults are normally distributed with a mean of 98.6 ° F and a... (answered by ewatrrr)
Assume the body temperatures of healthy adults are normally distributed with a mean of... (answered by stanbon)
Assume the body temperatures of healthy adults are normally distributed with a mean of... (answered by stanbon)
Healty people have body temperatures that are normally distributed with a mean of 98.20... (answered by stanbon)
A data set includes 109 body temperatures of healthy adult humans having a mean of 98.3 F  (answered by Theo)
A data set includes 108 body temperatures of healthy adult humans having a mean of... (answered by Boreal)
A sample of 110 adults has a mean body temperature of 98.18.

a.  Assuming that the... (answered by ewatrrr)
A data set includes 108 body temperatures of healthy adult humans having a mean of... (answered by robertb)