SOLUTION: 20 voters. 12 favor and 8 oppose. if 5 random voters are selected what is the probability that 3 will favor and 2 will oppose

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Question 610685: 20 voters. 12 favor and 8 oppose. if 5 random voters are selected what is the probability that 3 will favor and 2 will oppose

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
voters. 12 favor and 8 oppose.
5 random voters are selected...
P(3 in favor & 2 Opposed)= 12C3*8C2/20C5 = 220*28/15504
Can recommend Stattrek.com as a cross reference for your statistical calculations.
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