SOLUTION: Given belly button height (x) of students is normally distributed with a mean of 100cm and a standard deviation of 20cm. Find P(90 < x < 120). Given that X the random variable bel

Question 610069: Given belly button height (x) of students is normally distributed with a mean of 100cm and a standard deviation of 20cm. Find P(90 < x < 120).
Given that X the random variable belly button height (x) has a mean of 100 cm and standard deveiation of 20cm. Find belly button height x, such that P(belly button height [X] <=x) = 0.025.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Given belly button height (x) of students is normally distributed with a mean of 100cm and a standard deviation of 20cm. Find P(90 < x < 120).
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z(90) = (90-100)/20 = -10/20 = -1/2
z(120) = (120-100)/20 = 1
P(90 < x < 120) = P(-1/2 < z < 1) = 0.7263
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Given that X the random variable belly button height (x) has a mean of 100 cm and standard deveiation of 20cm. Find belly button height x, such that
P(belly button height [X] <=x) = 0.025.
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Find the z-value with a left tail of 0.025
z = invNorm(0.025) = -1.96
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Find "x" using x = zu + u
x = -1.96*20 + 100
x = 60.8 in
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Cheers,
Stan H.
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