SOLUTION: an urn contains 5 yellow, 6 green and 7 blue balls. two balls are randomly drawn without replacement. find the probability of the following events: A. both balls are green B. t

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Question 609930: an urn contains 5 yellow, 6 green and 7 blue balls. two balls are randomly drawn without replacement. find the probability of the following events:
A. both balls are green
B. the first ball is blue and the second is yellow
C. there is one green and one yellow ball

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
urn contains balls: 5 yellow, 6 green and 7 blue balls
two balls are randomly drawn 'without' replacement
A. P(both balls are green) =
B. P(the first ball is blue and the second is yellow) =
C. P(there is one green and one yellow ball)= 6C1*5C1/18C2 = 30/153 = 10/51
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