Hi

Note: The probability of x succesP(0)ses in n trials is: 

P = nCx*  where p and q are the probabilities of success and failure respectively. In this case p= .70 & q = .30 and n = 13

nCx = 

P( making >5) = 1 - [P(0)+P(1)+  P(2) + P(3) + P(4)+ P(5)]

P = 1-( ++++)= .9960

Recommend using TI or stattrek.com for statistical calculations.

Above is an explanatory presenation.  Hope this helps. 

Answer by htmentor(1343)   (Show Source): You can put this solution on YOUR website!
 This problem involves binomial probabilities

The binomial probability distribution is written as

P(x) = C(n,x)*p^x*(1-p)^(n-x) where n = the number of trials, x = the number of successes, and p is the probability of success

More than 5 throws means we need to compute the probability of 6 or more

P(6 or more) = 1 - P(5 or less)

P(5 or less) = P(5) + P(4) + ... P(0)

P(5) = C(13,5)*0.7^5*0.3^8 = 0.0142

.

.

.

Adding up all the probabilities and subtracting from 1, we get:

P(6 or more) = 1 - 0.018 = 0.982 

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