SOLUTION: The amount of Jen's monthly phone bill is normally distributed with a mean of $50 and a standard deviatin of $10. What is the 25th percentile?

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Question 609902: The amount of Jen's monthly phone bill is normally distributed with a mean of $50 and a standard deviatin of $10. What is the 25th percentile?
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 

Hi, understand now You were referring to this Inquiry

monthly phone bill is normally distributed with a mean of $50 and a standard deviation of $10

What is the 25th percentile: (x-50)/10 = -.6745  ||Note: NORMSINV(0.25)= -.6745

 (x-50)/10 = -.6745

    x  = $43.26  

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