SOLUTION: body temps: mean of 96.20 standard deviation of .82 If you have a body temp of 97.00 degrees, what is your percentile score?

Question 607381: body temps: mean of 96.20 standard deviation of .82
If you have a body temp of 97.00 degrees, what is your percentile score?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

mean of 96.20 standard deviation of .82

P(X=97) = P(z=(97-96.2)/.82) = P(z= .9756) = .8354 or 83.54%

                               Excel function: NORMSDIST(0.9756)= .8354 

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