SOLUTION: A bag of candy has 21 orange, 18 red, and 10 yellow candies. What is the probability that an orange will be drawn first and then a red (without replacement)? A. 31/49 B. 9/56

Algebra ->  Probability-and-statistics -> SOLUTION: A bag of candy has 21 orange, 18 red, and 10 yellow candies. What is the probability that an orange will be drawn first and then a red (without replacement)? A. 31/49 B. 9/56       Log On


   



Question 603924: A bag of candy has 21 orange, 18 red, and 10 yellow candies. What is the probability that an orange will be drawn first and then a red (without replacement)?
A. 31/49
B. 9/56
C. 27/175
D. 3/38

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
21 orange, 18 red, and 10 yellow candies - 49 total
two drawn (without replacement)?
P(orange and then a red)= %2821%2F49%29%2A%2818%2F48%29=%283%2F7%29%2A%283%2F8%29 = 9/56