SOLUTION: A bag of candy has 21 orange, 18 red, and 10 yellow candies. What is the probability that an orange will be drawn first and then a red (without replacement)? A. 31/49 B. 9/56

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Question 603924: A bag of candy has 21 orange, 18 red, and 10 yellow candies. What is the probability that an orange will be drawn first and then a red (without replacement)?
A. 31/49
B. 9/56
C. 27/175
D. 3/38

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
21 orange, 18 red, and 10 yellow candies - 49 total
two drawn (without replacement)?
P(orange and then a red)= = = 9/56
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