SOLUTION: Four cards are drawn without replacement from pack of cards . What is the probability that (a) they all are of different suit . (b) they all are aces.

Question 599423: Four cards are drawn without replacement from pack of cards . What is the probability that (a) they all are of different suit .
(b) they all are aces.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Four cards are drawn without replacement from pack of cards .
What is the probability that (
a) they all are of different suit.
# of ways to succeed: 13*13*13*13 = 28561
# of random results: 52C4 = 270725
P(4 of different suit) = 13^4/52C4 = 0.1055
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b) they all are aces.
# of ways to succeed: 1
# of random results 52C4
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P(4 aces) = 1/52C4 = 0.000003694
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Cheers,
Stan H.
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