SOLUTION: A container has 12 light bulbs, 4 of which are defective. Select 4 light bulbs. How many ways can we get 3 good and 1 bad light bulbs?

SOLUTION: A container has 12 light bulbs, 4 of which are defective. Select 4 light bulbs. How many ways can we get 3 good and 1 bad light bulbs?

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Question 599358: A container has 12 light bulbs, 4 of which are defective. Select 4 light bulbs. How many ways can we get 3 good and 1 bad light bulbs?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
(8 C 3)*(4 C 1) = [ (8!)/(3!(8-3)!) ] * [ (4!)/(1!(4-1)!) ] = 56*4 = 224

So there are 224 ways.
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