Question 597175: At a certain university, 15% of all the students have full-time jobs. You plan to take a large random sample of 140 students.
Use the Rule for Sample Proportions to describe the distribution of all possible sample proportions (p-hat values) for this situation. To do this, first find the mean and standard deviation of all sample proportions (show this work). Then, referring to the picture below, label the marked points by giving the appropriate proportion values for the seven blanks under the graph (using the entry boxes provided).
You are expected to enter your answers for this problem using leading zeros and exactly two (2) decimal places (if not, the computer might consider correct answers to be incorrect).
(Thus, if your answer is one-half, you'll enter 0.50...if your answer is one-third, you'll enter 0.33...if your answer is zero, you'll enter 0.00...etc.)
Mean =
St. Dev. =
Z = -3 -> p-hat =
Z = -2 -> p-hat =
Z = -1 -> p-hat =
Z = 0 -> p-hat =
Z = 1 -> p-hat =
Z = 2 -> p-hat =
Z = 3 -> p-hat =
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! At a certain university, 15% of all the students have full-time jobs. You plan to take a large random sample of 140 students.
Use the Rule for Sample Proportions to describe the distribution of all possible sample proportions (p-hat values) for this situation.
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To do this, first find the mean and standard deviation of all sample proportions (show this work).
Mean of the sample proportions = p = 0.15
Std of the sample proportions = sqrt(pq/n) = sqrt(0.15*0.85/140) = 0.0302
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Then, referring to the picture below, label the marked points by giving the appropriate proportion values for the seven blanks under the graph (using the entry boxes provided).
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You are expected to enter your answers for this problem using leading zeros and exactly two (2) decimal places (if not, the computer might consider correct answers to be incorrect).
(Thus, if your answer is one-half, you'll enter 0.50...if your answer is one-third, you'll enter 0.33...if your answer is zero, you'll enter 0.00...etc.)
Mean = 0.15
St. Dev. = 0.0302
Z = -3 -> p-hat = -3*0.0302+0.15 = 0.0594
Z = -2 -> p-hat = -2*0.0302+0.15 = 0.0896
etc.
The rest is arithmetic.
Cheers,
====================
Stan H.
Z = -1 -> p-hat =
Z = 0 -> p-hat =
Z = 1 -> p-hat =
Z = 2 -> p-hat =
Z = 3 -> p-hat =
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