# SOLUTION: There are eleven players on the basketball team. How many ways can a starting lineup of five players be chosen? I did 11x5 and got 55 but I dont think that is right.

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 Click here to see ALL problems on Probability-and-statistics Question 594224: There are eleven players on the basketball team. How many ways can a starting lineup of five players be chosen? I did 11x5 and got 55 but I dont think that is right.Answer by stanbon(57984)   (Show Source): You can put this solution on YOUR website!There are eleven players on the basketball team. How many ways can a starting lineup of five players be chosen? I did 11x5 and got 55 but I dont think that is right. -------------------- Ans: 11C5 = 11!/(6!*5!) = (11*10*9*8*7)/(1*2*3*4*5) = 462 ways ========================= Cheers, Stan H.