SOLUTION: There are eleven players on the basketball team. How many ways can a starting lineup of five players be chosen? I did 11x5 and got 55 but I dont think that is right.

Question 594224: There are eleven players on the basketball team. How many ways can a starting lineup of five players be chosen?
I did 11x5 and got 55 but I dont think that is right.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
There are eleven players on the basketball team. How many ways can a starting lineup of five players be chosen?
I did 11x5 and got 55 but I dont think that is right.
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Ans: 11C5 = 11!/(6!*5!) = (11*10*9*8*7)/(1*2*3*4*5) = 462 ways
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Cheers,
Stan H.
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