SOLUTION: find the probability of this set of an independent event.. I have a bag of 9 black checkers and 6 red checkers, I draw a red checker, I replace it and draw another red checker.

SOLUTION: find the probability of this set of an independent event.. I have a bag of 9 black checkers and 6 red checkers, I draw a red checker, I replace it and draw another red checker.

Algebra.Com

Question 592077: find the probability of this set of an independent event.. I have a bag of 9 black checkers and 6 red checkers, I draw a red checker, I replace it and draw another red checker.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
9+6=15
6/15=2/5 probability of the first checker being red.
6/15=2/5 probability of the second checker being red.
2/5 * 2/5 = 4/25 probability of them both being red.
.
Ed
RELATED QUESTIONS
A bag contains 7 black checkers and 3 red checkers. once a checker is picked it is not... (answered by Fombitz)

drawing a black checker from a bag of 9 black checkers and 6 red checkers, replacing it,... (answered by edjones)

I really need help on this math question: You have 8 red checkers and 8 black checkers (answered by rothauserc)

I really need help on this math question: You have 8 red checkers and 8 black checkers (answered by ikleyn)

There are 14 red checkers and 5 black checkers in a bag. Checkers are selected one at a... (answered by ewatrrr)

1. There are 12 red checkers and 3 black checkers in a bag. Checkers are selected one at... (answered by alexandramia)

There are 12 red checkers and 3 black checkers in a bag. Checkers are selected one at a... (answered by stanbon)

There are 20 red checkers and 8 black checkers in a bag. Checkers are selected one at a (answered by Fombitz)