SOLUTION: Suppose the chances of picking up a cold from someone by shaking hands with them is .01 (assuming you dont know whether they have a cold or not), and that each encounter you have i

Question 587077: Suppose the chances of picking up a cold from someone by shaking hands with them is .01 (assuming you dont know whether they have a cold or not), and that each encounter you have is independent of another.
Suppose you shake hands with 5 people in a given day. What is the probability that you dont pick up a cold from any of these people?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Suppose the chances of picking up a cold from someone by shaking hands with them is .01 (assuming you dont know whether they have a cold or not), and that each encounter you have is independent of another.
Suppose you shake hands with 5 people in a given day. What is the probability that you dont pick up a cold from any of these people?
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Binomial with n=5 ; p(catch) = 0.01 ; p(don't) = 0.99
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P(x = 5) = 0.99^5 = 0.0503
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Cheers,
Stan H.
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